هذا اللغز (مسألة حسابية) يبحث عن حل - من اول من يحله

[ACME]

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Three men in a cafe order a meal the total cost of which is $15. They each contribute $5. The waiter takes the money to the chef who recognizes the three as friends and asks the waiter to return $5 to the men.

The waiter is not only poor at mathematics but dishonest and instead of goi
ng to the trouble of splitting the $5 between the three he simply gives them $1 each and pockets the remaining $2 for himself.

Now, each of the men effectively paid $4, the total paid is therefore $12. Add the $2 in the waiters pocket and this comes to $14.....where has the other $1 gone from the original $15?

How Come
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[Dr_subahi]

Well,
If we count it from the chef's point of view it will be correct
for the meal 10 + 2 as a "tip" + 3 for each man the toltal will be 15

dr_subahi

[ACME]

Well,
If we count it from the chef's point of view it will be correct
for the meal 10 + 2 as a "tip" + 3 for each man the toltal will be 15

dr_subahi




Welcome back Dr_subahi . An utterly convincing answer
:smile (40):

Here is the answer in a another way

Answer:

The payments should equal the receipts. It does not make sense to add what was paid by the men ($12) to what was received from that payment by the waiter ($2)

Although the initial bill was $15 dollars, one of the five dollar notes gets changed into five ones. The total the three men ultimately paid is $12, as they get three ones back. So from the $12 the men paid, the owner receives $10 and the waiter receives the $2 difference. $15 - $3 = $10 + $2

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